leetcode33

解题思路

和二分没有太大的差别 思想还是分治法，只要设置好进入子区间不同的判定条件就好了

代码

class Solution {
public int search(int[] nums, int target) {
         if (nums.length == 0) {
            return -1;
        }
        int n = nums.length - 1;
        if (n == 0) {
            return nums[0] == target ? 0 : -1;
        }
        int s = 0, e = nums.length - 1;
        while (s <= e) {
            int mid = (e + s) / 2;
            if (nums[mid] == target) {
                return mid;
            }
            if (nums[mid] >=nums[s]) {
                if (nums[s] > target || nums[mid] < target) {
                    s = mid+1;
                } else {
                    e = mid-1;
                }
            } else {
                if (nums[mid] > target || nums[e] < target) {
                    e = mid-1;
                } else {
                    s = mid+1;
                }
            }
        }
        return -1;
    }
}